Real Estate & Moving, Ohio
Land Surveyor cost in Cleveland, OH
A typical Land Surveyor figure in Cleveland is about $606 per survey (residential boundary), about 13% below the national figure of $700.
Typical cost
Typical in Cleveland
$606
per survey (residential boundary)
- On the low end
- $303
- On the high end
- $1,040
Estimated from national price data, adjusted for the cost of living in Cleveland. Not a quote.
What moves the price
- Lot size
- Survey type
- Research
- Stakes
- Rush
Ways to pay less
- Order the type you actually need
- Share prior surveys
- Avoid rush
- Ask about ALTA extras
- Clear access to known corner markers
Land Surveyor in similar cities
| Place | Typical | Range |
|---|---|---|
| Cleveland, OH | $606 | $303 to $1,040 |
| National typical | $700 | $350 to $1,200 |
| Akron, OH | $581 | $291 to $996 |
| Cincinnati, OH | $686 | $343 to $1,175 |
| Dayton, OH | $634 | $317 to $1,085 |
| Baton Rouge, LA | $630 | $315 to $1,080 |
| Buffalo, NY | $658 | $329 to $1,130 |
Other Real Estate & Moving costs in Cleveland
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Questions people ask
Land Surveyor in Cleveland: what does it cost?
In Cleveland, OH, Land Surveyor typically costs about $606 per survey (residential boundary), with most prices between $303 and $1,040.
Why is Cleveland lower than the national price?
This estimate moves the national figure halfway with what the workers behind Land Surveyor earn in Cleveland, from federal wage data, and halfway with the local cost of living. Together they put Cleveland about 13% below the national figure.
Is this a quote?
No. It is an estimate built from national price data and local cost of living. A local pro will price your actual job.