Health & Wellness, Texas
Dental Implant cost in Brownsville, TX
A typical Dental Implant figure in Brownsville is about $3,120 per implant, about 22% below the national figure of $4,000.
Typical cost
Typical in Brownsville
$3,120
per implant
- On the low end
- $1,950
- On the high end
- $5,070
Estimated from national price data, adjusted for the cost of living in Brownsville. Insurance, coverage, and the details of your situation can change the real number a lot. Not a quote.
What moves the price
- Bone graft needed
- Crown material
- Specialist vs GP
- Number of implants
- Sedation
Ways to pay less
- Ask about 3D planning fees
- Compare specialist quotes
- Check if the crown is included
- Use dental tourism only with caution
- Ask about warranty
Dental Implant in similar cities
| Place | Typical | Range |
|---|---|---|
| Brownsville, TX | $3,120 | $1,950 to $5,070 |
| National typical | $4,000 | $2,500 to $6,500 |
| Laredo, TX | $3,200 | $2,000 to $5,200 |
| McAllen, TX | $3,200 | $2,000 to $5,200 |
| Amarillo, TX | $3,280 | $2,050 to $5,330 |
| Jackson, MS | $3,200 | $2,000 to $5,200 |
| Shreveport, LA | $3,200 | $2,000 to $5,200 |
Other Health & Wellness costs in Brownsville
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Questions people ask
Dental Implant in Brownsville: what does it cost?
In Brownsville, TX, Dental Implant typically costs about $3,120 per implant, with most prices between $1,950 and $5,070.
Why is Brownsville lower than the national price?
Prices in Brownsville run about 22% below the national average. This estimate scales the national figure by that difference in local cost of living.
Is this a quote?
No. It is an estimate built from national price data and local cost of living. A local pro will price your actual job.