Legal & Financial, Connecticut
Criminal Defense Attorney cost in Hartford, CT
A typical Criminal Defense Attorney figure in Hartford is about $5,300 per case, about 6% above the national figure of $5,000.
Typical cost
Typical in Hartford
$5,300
per case
- On the low end
- $1,590
- On the high end
- $21,200
Estimated from national price data, adjusted for the cost of living in Hartford. Insurance, coverage, and the details of your situation can change the real number a lot. Not a quote.
What moves the price
- Charge severity
- Trial vs plea
- Public vs private
- Experience
- Investigation
Ways to pay less
- Ask about payment plans
- Get a written scope
- Consider a public defender when appropriate
- Do not discuss the case publicly
- Request an early case assessment
Criminal Defense Attorney in similar cities
| Place | Typical | Range |
|---|---|---|
| Hartford, CT | $5,300 | $1,590 to $21,200 |
| National typical | $5,000 | $1,500 to $20,000 |
| New Haven, CT | $5,500 | $1,650 to $22,000 |
| Bridgeport, CT | $5,600 | $1,680 to $22,400 |
| Stamford, CT | $6,400 | $1,920 to $25,600 |
| Arvada, CO | $5,300 | $1,590 to $21,200 |
| Baltimore, MD | $5,300 | $1,590 to $21,200 |
Other Legal & Financial costs in Hartford
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Questions people ask
Criminal Defense Attorney in Hartford: what does it cost?
In Hartford, CT, Criminal Defense Attorney typically costs about $5,300 per case, with most prices between $1,590 and $21,200.
Why is Hartford higher than the national price?
Prices in Hartford run about 6% above the national average. This estimate scales the national figure by that difference in local cost of living.
Is this a quote?
No. It is an estimate built from national price data and local cost of living. A local pro will price your actual job.