Home & Repair, Texas
Concrete Contractor cost in Amarillo, TX
A typical Concrete Contractor figure in Amarillo is about $9.72 per square foot, about 19% below the national figure of $12.
Typical cost
Typical in Amarillo
$9.72
per square foot
- On the low end
- $4.86
- On the high end
- $18
Estimated from national price data, adjusted for the cost of living in Amarillo. Not a quote.
What moves the price
- Thickness
- Finish
- Demo
- Reinforcement
- Access
Ways to pay less
- Keep a simple broom finish
- Ask about control joints
- DIY only small pads that carry no weight
- Get mix specs
- Compare per-square-foot bids
Concrete Contractor in similar cities
| Place | Typical | Range |
|---|---|---|
| Amarillo, TX | $9.72 | $4.86 to $18 |
| National typical | $12 | $6.00 to $22 |
| El Paso, TX | $9.36 | $4.68 to $17 |
| Lubbock, TX | $9.96 | $4.98 to $19 |
| Laredo, TX | $9.60 | $4.80 to $18 |
| Montgomery, AL | $9.60 | $4.80 to $18 |
| Toledo, OH | $12 | $5.73 to $21 |
Other Home & Repair costs in Amarillo
Concrete Contractor in every cityEverything in AmarilloAll Home & Repair services
Questions people ask
Concrete Contractor in Amarillo: what does it cost?
In Amarillo, TX, Concrete Contractor typically costs about $9.72 per square foot, with most prices between $4.86 and $18.
Why is Amarillo lower than the national price?
This estimate moves the national figure halfway with what the workers behind Concrete Contractor earn in Amarillo, from federal wage data, and halfway with the local cost of living. Together they put Amarillo about 19% below the national figure.
Is this a quote?
No. It is an estimate built from national price data and local cost of living. A local pro will price your actual job.